How would you prepare a 10.0 mL of a 4 M solution
How would you prepare a 10.0 mL of a 4 M solution of maleic anhydride in CH2Cl2, and can you show all the calculations for this?
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How many mL of the 4 M maleic anhydride in CH2CL2 would be an equimolar amount?
Calculations for molar solutions are simple and can be deduced using the formula below:
M=x(In gms of solute)/Mol. Wt. of solute X 1L of Solvent
In this current example:
Molarity=4, Mol. Wt. of solute=98.06 (Usually found mentioned on the label of the bottle)
Hence 4=x/98.06 X 1000/10
x=(4 X 98.06 X 10)/1000
Therefore weigh 3.92g of Maleic anhydride and mix with 4-5ml of Dichloromethane. Once dissolved make up the volume to 10ml.
By furan are you referring to maleic anhydride or furan itself? In the next part of the question when you say equimolar..Its equimolar to what? A little clarification would be helpful in providing the answer.